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# Special condition for lambda?

## Question

Hello, in this article it is mentioned that

$\nu$ |

is an integer because of the ”boundary” condition that P is a periodic function but i don’t see any condition applied to the function Z (a usefule one in would be Z(

$\pm\infty$ |

)=0 ) therefore there is no contraint for the constant

$\lambda$ |

(and therefore

$\gamma$ |

, am I right?

but why is in the solution (e.g. eq. 17) a sum over all possible

$\gamma$ |

? shoud’nt it be an integral?

EDIT: maybe to make it more clear: if

$\gamma$ |

is an integer the solution is in principle a periodic function in z (equals a fourier series in z) but there is nothing that requieres this.

Context for the question:

What kind of question is this:

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